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| Before you get too disappointed, do the math yourself.
find area you what max. flow and temperature. Then find the
input temperature
The heater size in BTUs should be
Lbs. water/minute * temperature rise * 60/.95
assume it is 95% efficient
eg. 2 gallons/min. raising temp from 50 to 100F
2 * 8.3 * 50 * 60 / .95 = about 53000btu or about 15Kw electric unit
I did it here and came out with something over 100000BTU; thus
stayed with standard electric tank | |
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