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West Central Illinois | Assuming it’s about 9-10 feet high at the edge. Then about 9,000 bu.
24 feet radius
9.3 feet deep
Therefore=>
3.14x(24^2)x9.3=16,820 ft^3 is volume of cylinder
(3.14x(24^2)x9.3)/3 = 5,606 is volume of cone
16,820 - 5,600 = 11,213 cu feet left in bin
1.24 cu ft per bu
11,213/1.24 = 9,042 bu at 56 TW
9,042x58/56= 9,365 bu at 58 TW
So about 9,200 - 9,400 bu
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Bushels
