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Harvesting field efficiency
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wildcat1000
Posted 9/18/2024 16:04 (#10895295 - in reply to #10894948)
Subject: RE: Harvesting field efficiency


C IL
Muckcity561 - 9/18/2024 10:29

If I run at 2.5 mph with a 35-foot header, I found an equation from the internet: 2.5 × 35 ÷ 8.25 = 10.6. This gives me my acres per hour. However, I am not sure how to find my field efficiency to determine my final acres per hour. Could you please help me with this?


Get your stop watch . Time the actual harvesting minutes and seconds. Time the non harvesting minutes and seconds.

Harvest time/ total time = efficiency. You will see how much it changes as circumstances change.
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